MCQEasyJEE 2025Diodes & Rectifiers

JEE Physics 2025 Question with Solution

In the circuit shown, assuming the threshold voltage of the diode is negligibly small, then the voltage VABV_{AB} is correctly represented by:

Circuit diagram with an AC source on the left, a diode in the lower branch, resistor R in the right vertical branch, and output terminals A at top right and B at bottom right.Four waveform options for $$V_{AB}$$ versus time: positive half-wave pulses, sinusoidal AC wave, zero at all times, and negative half-wave pulses.
  • A

    positive half-wave rectified signal

  • B

    Full-wave rectified signal

  • C

    VABV_{AB} would be zero at all times

  • D

    negative half-wave rectified signal

Answer

Correct answer:B

Step-by-step solution

Standard Method

Given: The diode threshold voltage is negligibly small and the input is an AC signal. Find: The correct waveform of VABV_{AB}.

From the solution:

  • The circuit contains a diode and a resistor.
  • The input voltage is V0sinωtV_0 \sin \omega t.
  • the solution concludes that the output waveform is a full-wave rectified signal.

Therefore, the correct option is B.

Note: The source solution explicitly states full-wave rectified signal, so the answer is taken from the solution as required.

Using the extracted solution statement

Given: A diode-resistor circuit with negligible diode threshold. Find: Which shown waveform matches VABV_{AB}.

The extracted solution says:

Vinput=V0sinωtV_{\text{input}} = V_0 \sin \omega t

and then states that due to the nature of the diode, the output waveform is a full-wave rectified signal.

It further summarizes the output as: only positive half-cycles remain.

Hence, according to the provided the solution, the waveform corresponds to Option B.

Common mistakes

  • Assuming the diode allows both half-cycles to appear unchanged at the output. This is wrong because a diode conducts asymmetrically. Always check diode conduction separately in positive and negative half cycles.

  • Judging the answer only from the circuit sketch and ignoring the provided solution conclusion. Here, the extraction rule requires the solution to be the primary source for the final answer.

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