Physics Question from JEE Main 2023 · 10 April, Shift 2

If each diode has a forward bias resistance of $25 \, \Omega$ in the below circuit,

The figure shows: a rectangular circuit. The bottom branch holds the $5 \, \text{V}$ cell in series with a $25 \, \Omega$ resistor; the current it drives, $I_1$, is marked by an upward arrow on the left-hand vertical rail. Three identical branches run across from that left rail to the right-hand rail, each one a diode followed by a $125 \, \Omega$ resistor, with a rightward current arrow at its left end: the top branch carries $I_4$ through $D_1$, the second branch carries $I_3$ through $D_2$, and the third branch carries $I_2$ through $D_3$. $D_1$ and $D_3$ are drawn pointing right - anode on the left, cathode bar on the right, so along the direction of the branch arrows - while $D_2$ is drawn reversed, its cathode bar on the left and its triangle pointing back towards the rail.