Physics Question from JEE Main 2024 · 30 January, Shift 2

In the circuit described below, a $15 \, \text{V}$ battery drives a single series loop: leaving the positive terminal the current passes first through a germanium diode $D_1$ $(\text{Ge})$ and then through a silicon diode $D_2$ $(\text{Si})$, both connected in the forward direction, then through a $1.5 \, \text{k}\Omega$ resistor, and finally down through the load resistance $R_L = 2.5 \, \text{k}\Omega$ before returning to the negative terminal. The voltage across load resistance $R_L$ is: