MCQEasyJEE 2026Phenols

JEE Chemistry 2026 Question with Solution

Consider the following two reactions A and B:

Two benzene ring reactions labeled A and B. Reaction A shows phenol reacting with sodium to give main product and gas x. Reaction B shows benzoic acid reacting with sodium bicarbonate to give main product and gas y.

The numerical value of [molar mass of xx + molar mass of yy] is _____.

  • A

    4646

  • B

    8888

  • C

    160160

  • D

    44

Answer

Correct answer:A

Step-by-step solution

Standard Method

Given: In reaction A, phenol reacts with sodium and evolves gas xx. In reaction B, benzoic acid reacts with sodium bicarbonate and evolves gas yy.

Find: The numerical value of [molar mass of xx + molar mass of yy].

Phenol reacts with sodium to liberate hydrogen gas:

2C6H5OH+2Na2C6H5ONa+H22\mathrm{C_6H_5OH} + 2\mathrm{Na} \rightarrow 2\mathrm{C_6H_5ONa} + \mathrm{H_2}

So, gas xx is H2\mathrm{H_2}.

Molar mass of xx:

H2=2g mol1\mathrm{H_2} = 2 \, \text{g mol}^{-1}

Benzoic acid reacts with sodium bicarbonate to liberate carbon dioxide:

C6H5COOH+NaHCO3C6H5COONa+H2O+CO2\mathrm{C_6H_5COOH} + \mathrm{NaHCO_3} \rightarrow \mathrm{C_6H_5COONa} + \mathrm{H_2O} + \mathrm{CO_2}

So, gas yy is CO2\mathrm{CO_2}.

Molar mass of yy:

CO2=44g mol1\mathrm{CO_2} = 44 \, \text{g mol}^{-1}

Now add the two molar masses:

2+44=462 + 44 = 46

Therefore, the required numerical value is 4646. The correct option is A.

Common mistakes

  • Mistake: Assuming both reactions release the same gas because both compounds contain an acidic hydrogen. Why it is wrong: Phenol reacts with sodium to give H2\mathrm{H_2}, but carboxylic acids react with bicarbonate to give CO2\mathrm{CO_2}. What to do instead: Identify the reagent first, then recall the characteristic gas evolved.

  • Mistake: Taking the molar mass of phenol or benzoic acid instead of the gases xx and yy. Why it is wrong: The question asks only for the molar masses of the evolved gases. What to do instead: First determine the identities of xx and yy, then add only their molar masses.

  • Mistake: Using O2\mathrm{O_2} or atomic hydrogen instead of molecular hydrogen for gas xx. Why it is wrong: Sodium with phenol produces molecular hydrogen, that is H2\mathrm{H_2}, whose molar mass is 22, not 11 or 3232. What to do instead: Write the balanced reaction before calculating molar mass.

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