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MCQMediumJEE Main 2026 · 23 January, Shift 2Biot–Savart Law

Physics Question from JEE Main 2026 · 23 January, Shift 2

The current passing through a conducting loop in the form of equilateral triangle of side 43 cm4\sqrt{3} \, \text{cm} is 2 A2 \, \text{A}. The magnetic field at its centroid is α×10−5 T\alpha \times 10^{-5} \, \text{T}. The value of α\alpha is _____. (Given : μ0=4π×10−7\mu_0 = 4\pi \times 10^{-7} SI units)

  • A

    333\sqrt{3}

  • B

    232\sqrt{3}

  • C

    3\sqrt{3}

  • D

    32\frac{\sqrt{3}}{2}

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