Physics Question from JEE Main 2025 · 24 January, Shift 1

A current of $5 \, \text{A}$ exists in a square loop of side $\frac{1}{\sqrt{2}} \, \text{m}$. Then the magnitude of the magnetic field $B$ at the centre of the square loop will be $p \times 10^{-6} \, \text{T}$. Where, value of $p$ is: [Take $\mu_0 = 4\pi \times 10^{-7} \, \text{T m A}^{-1}$]