MCQMediumJEE Main 2025 · 28 January, Shift 2Biot–Savart Law

Physics Question from JEE Main 2025 · 28 January, Shift 2

An infinite wire has a circular bend of radius aa, and carrying a current II as shown in the figure. The magnitude of the magnetic field at the origin OO of the arc is given by:

A wire forms a three-fourth circular arc centered at O with radius a, then extends horizontally to the right and also as a lower straight segment to infinity, with current directions marked on the arc and straight parts.
  • A

    μ0I4πa(3π2+2)\frac{\mu_0 I}{4 \pi a} \left( \frac{3\pi}{2} + 2 \right)

  • B

    μ0I2πa(π2+2)\frac{\mu_0 I}{2 \pi a} \left( \frac{\pi}{2} + 2 \right)

  • C

    μ0I4πa(3π2+1)\frac{\mu_0 I}{4 \pi a} \left( \frac{3\pi}{2} + 1 \right)

  • D

    μ0I4πa(π2+1)\frac{\mu_0 I}{4 \pi a} \left( \frac{\pi}{2} + 1 \right)

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Practice more Biot–Savart Law questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Related questions