NVAMediumJEE Main 2025 · 22 January, Shift 2Biot–Savart Law

Physics Question from JEE Main 2025 · 22 January, Shift 2

Two long parallel wires X and Y, separated by a distance of 6cm6 \, \text{cm}, carry currents of 5A5 \, \text{A} and 4A4 \, \text{A}, respectively, in opposite directions as shown in the figure. The magnitude of the resultant magnetic field at point P, at a distance of 4cm4 \, \text{cm} from wire Y, is x×105Tx \times 10^{-5} \, \text{T}. The value of xx is _____. (Take permeability of free space as μ0=4π×107\mu_0 = 4\pi \times 10^{-7} SI units.)

Two long parallel vertical wires X and Y are 6 cm apart. Wire X carries 5 A upward, wire Y carries 4 A downward, and point P lies 4 cm beyond wire Y on the far side from X.

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