MCQMediumJEE Main 2025 · 8 April, Shift 2Carboxylic Acids

Chemistry Question from JEE Main 2025 · 8 April, Shift 2

Reaction scheme showing compound A converting to B using NaOH followed by H3O+, then B converting to C using EtOH and H2SO4 under heat.

A shows positive Lassaigne's test for N and its molar mass is 121121

B gives effervescence with aqueous NaHCO3\text{NaHCO}_3

C gives fruity smell.

Identify A, B, and C from the following.

  • A

    A = benzamide C6H5CONH2\mathrm{C_6H_5CONH_2}, B = benzoic acid C6H5CO2H\mathrm{C_6H_5CO_2H}, C = ethyl benzoate C6H5CO2Et\mathrm{C_6H_5CO_2Et}

  • B

    A = benzylhydrazine C6H5CH2NHNH2\mathrm{C_6H_5CH_2NHNH_2}, B = benzoic acid C6H5CO2H\mathrm{C_6H_5CO_2H}, C = ethyl benzoate C6H5CO2Et\mathrm{C_6H_5CO_2Et}

  • C

    A = 4-aminobenzaldehyde, B = the benzoin (4-H2N-C6H4)CH(OH)CO(C6H4-4-NH2)\mathrm{(4\text{-}H_2N\text{-}C_6H_4)CH(OH)CO(C_6H_4\text{-}4\text{-}NH_2)}, C = its ethyl hemiketal (4-H2N-C6H4)CH(OH)C(OH)(OEt)(C6H4-4-NH2)\mathrm{(4\text{-}H_2N\text{-}C_6H_4)CH(OH)C(OH)(OEt)(C_6H_4\text{-}4\text{-}NH_2)}

  • D

    A = 2-aminobenzaldehyde, B = 2-aminobenzoic acid (2-H2N-C6H4CO2H)\mathrm{(2\text{-}H_2N\text{-}C_6H_4CO_2H)}, C = ethyl 2-(ethylamino)benzoate (2-EtHN-C6H4CO2Et)\mathrm{(2\text{-}EtHN\text{-}C_6H_4CO_2Et)}

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