NVAMediumJEE Main 2025 · 8 April, Shift 2Cross Product

Mathematics Question from JEE Main 2025 · 8 April, Shift 2

Let the area of the triangle formed by the lines x+2=y1=zx + 2 = y - 1 = z, x35=y1=z11\frac{x - 3}{5} = \frac{y}{-1} = \frac{z - 1}{1} and x3=y33=z21\frac{x}{-3} = \frac{y - 3}{3} = \frac{z - 2}{1} be AA. Then A2A^2 is equal to:

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Practice more Cross Product questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Related questions