MCQMediumJEE Main 2026 · 23 January, Shift 1Cross Product

Mathematics Question from JEE Main 2026 · 23 January, Shift 1

Let a=i^+j^+2k^\vec{a} = -\hat{i} + \hat{j} + 2\hat{k}, b=i^j^3k^\vec{b} = \hat{i} - \hat{j} - 3\hat{k}, c=a×b\vec{c} = \vec{a} \times \vec{b} and d=c×a\vec{d} = \vec{c} \times \vec{a}. Then (ab)d(\vec{a} - \vec{b}) \cdot \vec{d} is equal to:

  • A

    4-4

  • B

    44

  • C

    2-2

  • D

    22

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