MCQEasyJEE Main 2026 · 23 January, Shift 2Cross Product

Mathematics Question from JEE Main 2026 · 23 January, Shift 2

Let a⃗,b⃗,c⃗\vec{a}, \vec{b}, \vec{c} be three vectors such that a⃗×b⃗=2(a⃗×c⃗)\vec{a} \times \vec{b} = 2(\vec{a} \times \vec{c}). If ∣a⃗∣=1|\vec{a}| = 1, ∣b⃗∣=4|\vec{b}| = 4, ∣c⃗∣=2|\vec{c}| = 2, and the angle between b⃗\vec{b} and c⃗\vec{c} is 60∘60^\circ, then ∣a⃗⋅c⃗∣|\vec{a} \cdot \vec{c}| is equal to

  • A

    44

  • B

    22

  • C

    00

  • D

    11

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