MCQMediumJEE Main 2026 · 21 January, Shift 1Cross Product

Mathematics Question from JEE Main 2026 · 21 January, Shift 1

Let a=i^+2j^+2k^\vec{a} = -\hat{i} + 2\hat{j} + 2\hat{k}, b=8i^+7j^3k^\vec{b} = 8\hat{i} + 7\hat{j} - 3\hat{k} and c\vec{c} be a vector such that a×c=b\vec{a} \times \vec{c} = \vec{b}. If c(i^+j^+k^)=4\vec{c} \cdot (\hat{i}+\hat{j}+\hat{k}) = 4, then a+c2|\vec{a}+\vec{c}|^2 is equal to:

  • A

    3333

  • B

    3535

  • C

    2727

  • D

    3030

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