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MCQMediumJEE Main 2025 · 7 April, Shift 1Skew Lines & Shortest Distance

Mathematics Question from JEE Main 2025 · 7 April, Shift 1

If the shortest distance between the lines x−12=y−23=z−34\frac{x-1}{2} = \frac{y-2}{3} = \frac{z-3}{4} and x1=yα=z−51\frac{x}{1} = \frac{y}{\alpha} = \frac{z-5}{1} is 56\frac{5}{\sqrt{6}}, then the sum of all possible values of α\alpha is:

  • A

    32\frac{3}{2}

  • B

    −32\frac{-3}{2}

  • C

    33

  • D

    −3-3

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