MCQMediumJEE Main 2026 · 22 January, Shift 1Skew Lines & Shortest Distance

Mathematics Question from JEE Main 2026 · 22 January, Shift 1

Let P(α,β,γ)P(\alpha, \beta, \gamma) be the point on the line x12=y+13=z\frac{x-1}{2} = \frac{y+1}{-3} = z at a distance 4144\sqrt{14} from the point (1,1,0)(1,-1,0) and nearer to the origin. Then the shortest distance between the lines xα1=yβ2=zγ3\frac{x-\alpha}{1} = \frac{y-\beta}{2} = \frac{z-\gamma}{3} and x+52=y101=z31\frac{x+5}{2} = \frac{y-10}{1} = \frac{z-3}{1} is equal to

  • A

    7547\sqrt{\frac{5}{4}}

  • B

    4574\sqrt{\frac{5}{7}}

  • C

    2742\sqrt{\frac{7}{4}}

  • D

    4754\sqrt{\frac{7}{5}}

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