MCQMediumJEE Main 2025 · 23 January, Shift 2Skew Lines & Shortest Distance

Mathematics Question from JEE Main 2025 · 23 January, Shift 2

If the square of the shortest distance between the lines x21=y12=z+33\frac{x-2}{1} = \frac{y-1}{2} = \frac{z+3}{-3} and x+12=y+34=z+55\frac{x+1}{2} = \frac{y+3}{4} = \frac{z+5}{-5} is mn\frac{m}{n}, where mm and nn are co-prime numbers, then m+nm+n is equal to:

  • A

    66

  • B

    99

  • C

    2121

  • D

    1414

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