MCQMediumJEE Main 2026 · 24 January, Shift 2Skew Lines & Shortest Distance

Mathematics Question from JEE Main 2026 · 24 January, Shift 2

The sum of all values of α\alpha, for which the shortest distance between the lines x+1α=y21=z4α\dfrac{x+1}{\alpha}=\dfrac{y-2}{-1}=\dfrac{z-4}{-\alpha} and xα=y12=z12α\dfrac{x}{\alpha}=\dfrac{y-1}{2}=\dfrac{z-1}{2\alpha} is 2\sqrt{2}, is

  • A

    66

  • B

    6-6

  • C

    8-8

  • D

    88

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