MCQMediumJEE Main 2025 · 2 April, Shift 2Cross Product

Mathematics Question from JEE Main 2025 · 2 April, Shift 2

Let a=2i^3j^+k^\vec{a} = 2\hat{i} - 3\hat{j} + \hat{k}, b=3i^+2j^+5k^\vec{b} = 3\hat{i} + 2\hat{j} + 5\hat{k} and a vector c\vec{c} be such that (ac)×b=18i^3j^+12k^(\vec{a} - \vec{c}) \times \vec{b} = -18\hat{i} - 3\hat{j} + 12\hat{k} and ac=3\vec{a} \cdot \vec{c} = 3. If b×c=d\vec{b} \times \vec{c} = \vec{d}, then ad\left|\vec{a} \cdot \vec{d}\right| is equal to:

  • A

    1818

  • B

    1212

  • C

    99

  • D

    1515

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