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MCQMediumJEE Main 2025 · 29 January, Shift 2Trigonometric Ratios & Identities

Mathematics Question from JEE Main 2025 · 29 January, Shift 2

If sin⁡x+sin⁡2x=1\sin x + \sin^2 x = 1, x∈(0,π2)x \in \left(0, \frac{\pi}{2} \right), then the expression

(cos⁡12x+tan⁡12x)+3(cos⁡10x+tan⁡10x+cos⁡8x+tan⁡8x)+(cos⁡6x+tan⁡6x)(\cos^{12} x + \tan^{12} x) + 3(\cos^{10} x + \tan^{10} x + \cos^{8} x + \tan^{8} x) + (\cos^{6} x + \tan^{6} x)

is equal to:

  • A

    44

  • B

    33

  • C

    22

  • D

    11

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