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MCQMediumJEE Main 2026 · 23 January, Shift 2Trigonometric Ratios & Identities

Mathematics Question from JEE Main 2026 · 23 January, Shift 2

Let π2<θ<π\frac{\pi}{2} < \theta < \pi and cot⁡θ=−122\cot \theta = -\frac{1}{2\sqrt{2}}. Then the value of

sin⁡(15θ2)(cos⁡8θ+sin⁡8θ)+cos⁡(15θ2)(cos⁡8θ−sin⁡8θ)\sin\left(\frac{15\theta}{2}\right)\left(\cos 8\theta + \sin 8\theta\right) + \cos\left(\frac{15\theta}{2}\right)\left(\cos 8\theta - \sin 8\theta\right)

is equal to

  • A

    2−13\frac{\sqrt{2}-1}{\sqrt{3}}

  • B

    23\frac{\sqrt{2}}{\sqrt{3}}

  • C

    1−23\frac{1-\sqrt{2}}{\sqrt{3}}

  • D

    −23-\frac{\sqrt{2}}{\sqrt{3}}

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