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NVAMediumJEE Main 2026 · 22 January, Shift 1Trigonometric Ratios & Identities

Mathematics Question from JEE Main 2026 · 22 January, Shift 1

If cos⁡248∘−sin⁡212∘sin⁡224∘−sin⁡26∘=α+β52\frac{\cos^2 48^\circ - \sin^2 12^\circ}{\sin^2 24^\circ - \sin^2 6^\circ} = \frac{\alpha + \beta\sqrt{5}}{2}, where α,β∈N\alpha, \beta \in \mathbb{N}, then the value of α+β\alpha + \beta is _____.

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