MCQMediumJEE Main 2026 · 23 January, Shift 2Trigonometric Ratios & Identities

Mathematics Question from JEE Main 2026 · 23 January, Shift 2

The sum of all the real solutions of the equation

log(x+3)(6x2+28x+30)=52log(6x+10)(x2+6x+9)\log_{(x+3)}(6x^2 + 28x + 30) = 5 - 2\log_{(6x+10)}(x^2 + 6x + 9) is equal to

  • A

    11

  • B

    00

  • C

    22

  • D

    44

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