JEE Physics 2025 Question with Solution

Given: The distance covered is to be found from the velocity-time graph between $t = 0$ and $t = 4 \, \text{s}$.

Find: The distance covered by the object in this interval.

The solution states that in a velocity-time graph, the distance covered is the area under the graph. It further concludes:

Therefore, the correct option is A, and the distance covered is $13 \, \text{m}$.

There is a discrepancy in the extracted solution content: one approach on the page discusses geometric regions that would give $30 \, \text{m}$ for a graph with markings $0, 2, 4, 6$ and height $10 \, \text{m/s}$, but the page itself explicitly marks Option A as correct and states the distance as $13 \, \text{m}$. Following the solution's authority, the answer is taken as A.

Given: A velocity-time graph is shown, and the question asks for distance from $t = 0$ to $t = 4 \, \text{s}$.

Find: Area under the graph in the given interval.

Principle: Distance covered from a velocity-time graph equals the area under the graph over the required time interval.

The hint on the page says to use the geometry of the regions under the graph. The page's final extracted conclusion is:

Hence, the correct option is A.

Because the numerical labels visible in the extracted figure can suggest a different area if read directly, the safest grounded conclusion is to follow the page's declared correct option and final boxed answer. Therefore, the distance covered is $13 \, \text{m}$.