MCQMediumJEE Main 2025 · 28 January, Shift 2Trigonometric Ratios & Identities

Mathematics Question from JEE Main 2025 · 28 January, Shift 2

The value of r=1131sin(π4+(r1)π6)sin(π4+rπ6)=a3+b\sum_{r=1}^{13} \frac{1}{\sin\left(\frac{\pi}{4} + (r-1)\frac{\pi}{6}\right)\sin\left(\frac{\pi}{4} + r\frac{\pi}{6}\right)} = a\sqrt{3} + b, where a,bZa, b \in \mathbb{Z}. Then a2+b2a^2 + b^2 is equal to:

  • A

    1010

  • B

    44

  • C

    88

  • D

    22

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