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JEE Chemistry 2025 Question with Solution

Consider the following sequence of reactions: \includegraphics[width=0.5\linewidth]{74.png 11.25 mg of chlorobenzene will produce x×10−1x \times 10^{-1} mg of product B. Consider the reactions result in complete conversation. Given molar mass of C, H, O, N, and Cl as 12, 1, 16, 14, and 35.5 g mol−1^{-1}, respectively, the value of xx is:

Answer

Correct answer:9

Step-by-step solution

Standard Method

Given: 11.25 mg11.25 \, \text{mg} of chlorobenzene is used. The problem asks for the value of xx in x×10−1x \times 10^{-1} mg of product B.

Find: The value of xx.

From the solution:

  1. Determine the moles of chlorobenzene.
Moles of chlorobenzene=11.25 mg1 g/mol=11.25×10−3C6H5Cl\text{Moles of chlorobenzene} = \frac{11.25 \, \text{mg}}{1 \, \text{g/mol}} = \frac{11.25 \times 10^{-3}}{C_6H_5Cl}
  1. Calculate the corresponding amount of product B after completing the reaction.

The extracted solution concludes directly that the value of xx is 99.

Therefore, the required answer is 99.

Common mistakes

  • Using the mass directly in mg without converting consistently during stoichiometric calculation is incorrect. Always keep units consistent before applying mole relations.

  • Trying to derive the product amount without the full reaction scheme can lead to unsupported assumptions. Here, the reliable conclusion must be taken from the solution, which states the final value of xx.

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