MCQMediumJEE Main 2025 · 24 January, Shift 2Cross Product

Mathematics Question from JEE Main 2025 · 24 January, Shift 2

Let a=3i^j^+2k^\mathbf{a} = 3\hat{i} - \hat{j} + 2\hat{k}, b=a×(i^2k^)\mathbf{b} = \mathbf{a} \times (\hat{i} - 2\hat{k}) and c=b×k^\mathbf{c} = \mathbf{b} \times \hat{k}. Then the projection of c2j^\mathbf{c} - 2\hat{j} on a\mathbf{a} is:

  • A

    2142\sqrt{14}

  • B

    272\sqrt{7}

  • C

    373\sqrt{7}

  • D

    14\sqrt{14}

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Practice more Cross Product questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Related questions