MCQMediumJEE 2025Entropy & Spontaneity

JEE Chemistry 2025 Question with Solution

The effect of temperature on the spontaneity of reactions are represented as:

ΔHΔSTemperatureSpontaneity+any TNon spontaneous++low Tspontaneouslow TNon spontaneous+any Tspontaneous\begin{array}{|c|c|c|c|} \hline \Delta H & \Delta S & \text{Temperature} & \text{Spontaneity}\\ \hline + & - & \text{any } T & \text{Non spontaneous}\\ + & + & \text{low } T & \text{spontaneous}\\ - & - & \text{low } T & \text{Non spontaneous}\\ - & + & \text{any } T & \text{spontaneous}\\ \hline \end{array}

Which of the following is correct?

  • A

    (B) and (D) only

  • B

    (A) and (D) only

  • C

    (B) and (C) only

  • D

    (A) and (C) only

Answer

Correct answer:C

Step-by-step solution

Standard Method

Given: The signs of ΔH\Delta H and ΔS\Delta S are listed with the stated temperature conditions for spontaneity.

Find: Which statements are correct.

Use the Gibbs free energy relation:

ΔG=ΔHTΔS\Delta G = \Delta H - T\Delta S

A reaction is spontaneous when ΔG<0\Delta G < 0.

Now check each case:

  1. If ΔH>0\Delta H > 0 and ΔS<0\Delta S < 0, then both terms make ΔG\Delta G positive. So the reaction is non-spontaneous at any temperature. This statement is correct.
  2. If ΔH>0\Delta H > 0 and ΔS>0\Delta S > 0, the reaction becomes spontaneous at high temperature, not low temperature. So this statement is incorrect.
  3. If ΔH<0\Delta H < 0 and ΔS<0\Delta S < 0, the reaction is spontaneous at low temperature. Therefore saying non-spontaneous at low temperature is incorrect.
  4. If ΔH<0\Delta H < 0 and ΔS>0\Delta S > 0, both terms favor ΔG<0\Delta G < 0, so the reaction is spontaneous at any temperature. This statement is correct.

Therefore, the correct statements are (A) and (D), which corresponds to option B.

The solution also contains a conflicting line claiming option C, but the detailed Gibbs free energy analysis supports option B.

Common mistakes

  • Assuming ΔH>0\Delta H > 0 and ΔS>0\Delta S > 0 gives spontaneity at low temperature. This is wrong because the TΔS-T\Delta S term becomes more negative only at high temperature. Check how temperature changes the magnitude of TΔST\Delta S.

  • Treating ΔH<0\Delta H < 0 and ΔS<0\Delta S < 0 as non-spontaneous at low temperature. This is wrong because at low temperature the enthalpy term can dominate and keep ΔG\Delta G negative. Evaluate the temperature dependence before deciding.

  • Memorizing the spontaneity table incorrectly without using ΔG=ΔHTΔS\Delta G = \Delta H - T\Delta S. This can lead to sign mistakes. Re-derive each case from the Gibbs free energy equation whenever unsure.

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