Ice at -5^° C is heated to become vapor with temperature of 110^° C at atmospheric pressure. The entropy chang…

Question

Ice at $$-5^\circ C$$ is heated to become vapor with temperature of $$110^\circ C$$ at atmospheric pressure. The entropy change associated with this process can be obtained from:

Accepted Answer

B. $$\int_{268 \, K}^{273 \, K} \frac{C_{p,m}}{T} \, dT + \frac{\Delta H_{m,	ext{fusion}}}{T_f} + \frac{\Delta H_{m,	ext{vaporisation}}}{T_b} + \int_{273 \, K}^{373 \, K} \frac{C_{p,m}}{T} \, dT + \int_{373 \, K}^{383 \, K} \frac{C_{p,m}}{T} \, dT$$

Answer

A. $$\int_{268 \, K}^{383 \, K} C_p \, dT + \frac{\Delta H_{melting}}{273} + \frac{\Delta H_{boiling}}{373}$$

Answer

C. $$\int_{268 \, K}^{373 \, K} C_p \, dT + q_{rev}$$

Answer

D. $$\int_{268 \, K}^{273 \, K} C_{p,m} \, dT + \frac{\Delta H_{m,	ext{fusion}}}{T_f} + \frac{\Delta H_{m,	ext{vaporisation}}}{T_b} + \int_{273 \, K}^{373 \, K} C_{p,m} \, dT + \int_{373 \, K}^{383 \, K} C_{p,m} \, dT$$

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