MCQEasyJEE 2025Interference (Young's Experiment)

JEE Physics 2025 Question with Solution

Given below are two statements, one labeled as Assertion (A) and the other as Reason (R). Assertion (A): In Young’s double slit experiment, the fringes produced by red light are closer compared to those produced by blue light. Reason (R): The fringe width is directly proportional to the wavelength of light. In the light of the above statements, choose the correct answer from the options given below:

  • A

    Both (A) and (R) are true, but (R) is NOT the correct explanation of (A).

  • B

    (A) is false, but (R) is true.

  • C

    Both (A) and (R) are true, and (R) is the correct explanation of (A).

  • D

    (A) is true, but (R) is false.

Answer

Correct answer:B

Step-by-step solution

Standard Method

Given: Assertion says that in Young’s double slit experiment, fringes produced by red light are closer than those produced by blue light. Reason says that fringe width is directly proportional to wavelength.

Find: Which option correctly describes the truth of Assertion (A) and Reason (R).

The fringe width in Young’s double slit experiment is given by

β=λDd\beta = \frac{\lambda D}{d}

where λ\lambda is the wavelength of light, DD is the distance between slits and screen, and dd is the slit separation.

From the formula,

βλ\beta \propto \lambda

So, a larger wavelength produces a larger fringe width.

Red light has greater wavelength than blue light, so red light produces wider fringes, not closer fringes.

Therefore, Assertion (A) is false.

The Reason (R) states that fringe width is directly proportional to wavelength, which is true.

Therefore, the correct option is B.

Stepwise Verification

Given:

  • Assertion (A): red light produces fringes closer than blue light.
  • Reason (R): fringe width is directly proportional to wavelength.

Find: Decide the correct option.

Step 1: Use the fringe width relation:

β=λDd\beta = \frac{\lambda D}{d}

Step 2: Compare dependence on wavelength:

βλ\beta \propto \lambda

Thus, fringe width increases when wavelength increases.

Step 3: Compare red and blue light. Since wavelength of red light is greater than wavelength of blue light,

λr>λb\lambda_r > \lambda_b

Hence,

βr>βb\beta_r > \beta_b

So, fringes due to red light are wider apart, not closer.

Step 4: Judge the statements.

  • Assertion (A) is false.
  • Reason (R) is true.

Therefore, the correct option is B.

Common mistakes

  • Students may think red light gives closer fringes because it is often associated with lower energy. Fringe width depends on wavelength, not energy. Use β=λDd\beta = \frac{\lambda D}{d} and compare wavelengths directly.

  • A common mistake is to remember the formula incorrectly as fringe width being inversely proportional to wavelength. That is wrong. The correct relation is βλ\beta \propto \lambda, so larger wavelength gives wider fringes.

  • Some students compare frequency instead of wavelength without converting the relation properly. In this experiment, the direct formula uses wavelength, so compare red and blue using their wavelengths first.

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