In a double slit experiment the distance between the slits is 0.1 cm and the screen is placed at 50 cm from th…

Question

In a double slit experiment the distance between the slits is $0.1 \, \text{cm}$ and the screen is placed at $50 \, \text{cm}$ from the slits plane. When one slit is covered with a transparent sheet having thickness $t$ and refractive index $n(=1.5)$ , the central fringe shifts by $0.2 \, \text{cm}$ . The value of $t$ is _____ $\text{cm}$ .

A
$8 \times 10^{-4}$
B
$6.0 \times 10^{-3}$
C
$5.0 \times 10^{-3}$
D
$5.6 \times 10^{-4}$

Accepted Answer

A. $$8 	imes 10^{-4}$$

Answer

B. $$6.0 	imes 10^{-3}$$

Answer

C. $$5.0 	imes 10^{-3}$$

Answer

D. $$5.6 	imes 10^{-4}$$

Answer & step-by-step solution

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