MCQMediumJEE Main 2024 · 1 February, Shift 2Trigonometric Ratios & Identities

Mathematics Question from JEE Main 2024 · 1 February, Shift 2

The number of solutions of the equation 4sin2x4cos3x+94cosx=04 \sin^2 x - 4 \cos^3 x + 9 - 4 \cos x = 0, for x[2π,2π]x \in [-2\pi, 2\pi], is:

  • A

    11

  • B

    33

  • C

    22

  • D

    00

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