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JEE Mathematics 2024 Question with Solution

An integer is chosen at random from the integers 11, 22, 33, ..., 5050. The probability that the chosen integer is a multiple of at least one of 44, 66, 77 is:

  • A

    825\frac{8}{25}

  • B

    2150\frac{21}{50}

  • C

    950\frac{9}{50}

  • D

    1425\frac{14}{25}

Answer

Correct answer:B

Step-by-step solution

Standard Method

Given: An integer is chosen uniformly from 11 to 5050.

Find: The probability that it is divisible by at least one of 44, 66, 77.

Use the principle of inclusion-exclusion.

Number of multiples of 44 in 11 to 5050 is 1212.

Number of multiples of 66 in 11 to 5050 is 88.

Number of multiples of 77 in 11 to 5050 is 77.

Now count common multiples of pairs:

  • LCM(4,6)=12(4,6) = 12, so common multiples of 44 and 66 are 44.
  • LCM(6,7)=42(6,7) = 42, so common multiples of 66 and 77 are 11.
  • LCM(4,7)=28(4,7) = 28, so common multiples of 44 and 77 are 11.

For all three numbers,

LCM(4,6,7)=84\operatorname{LCM}(4,6,7) = 84

Since 84>5084 > 50, the number of multiples common to all three is 00.

Applying inclusion-exclusion,

N(467)=12+8+7411+0=21\begin{aligned} N(4 \cup 6 \cup 7) &= 12 + 8 + 7 - 4 - 1 - 1 + 0 \\ &= 21 \end{aligned}

Probability Form

Let AA be the event that the chosen integer is a multiple of 44, BB the event that it is a multiple of 66, and CC the event that it is a multiple of 77.

Then,

P(A)=1250,P(B)=850,P(C)=750P(A) = \frac{12}{50}, \qquad P(B) = \frac{8}{50}, \qquad P(C) = \frac{7}{50}

Common mistakes

  • Counting multiples of 44, 66, 77 separately and adding them directly is wrong because numbers like 1212 and 2828 get counted more than once. Use inclusion-exclusion to correct for overlap.

  • Using the product 4×64 \times 6 instead of LCM(4,6)(4,6) for common multiples is incorrect. Common multiples are counted using the least common multiple, so use 1212, not 2424.

  • Forgetting to check whether LCM(4,6,7)=84\operatorname{LCM}(4,6,7) = 84 lies within the range 11 to 5050 leads to an incorrect triple-intersection count. Since 84>5084 > 50, this contribution is 00.

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