Two distinct numbers and are selected at random from . The probability that their product is divisible by is
- A
- B
- C
- D
Two distinct numbers and are selected at random from . The probability that their product is divisible by is
Correct answer:C
Standard Method
Given: Two distinct numbers and are chosen from .
Find: The probability that is divisible by .
The total number of ways to choose two distinct numbers is
Numbers divisible by in are , so their count is
Hence, the count of numbers not divisible by is
Use the complementary event: is not divisible by only when neither nor is divisible by .
So the number of such selections is
Therefore, the number of favorable selections is
So the required probability is
The solution lists option B and final answer , but the working clearly gives . Therefore, the correct option from the given choices is C.
Complement Counting Shortcut
Given: Two distinct numbers are selected from to .
Find: Probability that the product is divisible by .
Instead of directly counting cases where at least one number is divisible by , count the opposite case first.
There are multiples of up to , so there are numbers not divisible by . The product fails to be divisible by only if both chosen numbers come from these numbers.
Thus,
Hence,
Therefore, the correct option is C.
Counting as the required probability. This is the probability that neither selected number is divisible by , so the product is not divisible by . Use the complement to get the required probability.
Using ordered pairs instead of unordered selections. The question selects two distinct numbers, so the total outcomes are , not .
Miscounting the multiples of up to . The sequence ends at , so the correct count is , obtained from .
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