MCQMediumJEE Main 2024 · 31 January, Shift 1Cross Product

Mathematics Question from JEE Main 2024 · 31 January, Shift 1

Let a=3i^+j^2k^\vec{a} = 3\hat{i} + \hat{j} - 2\hat{k}, b=4i^+j^+7k^\vec{b} = 4\hat{i} + \hat{j} + 7\hat{k} and c=i^3j^+4k^\vec{c} = \hat{i} - 3\hat{j} + 4\hat{k} be three vectors. If a vector p\vec{p} satisfies p×b=c×b\vec{p} \times \vec{b} = \vec{c} \times \vec{b} and pa=0\vec{p} \cdot \vec{a} = 0, then p(i^j^k^)\vec{p} \cdot (\hat{i} - \hat{j} - \hat{k}) is equal to:

  • A

    2424

  • B

    3636

  • C

    2828

  • D

    3232

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