MCQMediumJEE Main 2024 · 30 January, Shift 2Biot–Savart Law

Physics Question from JEE Main 2024 · 30 January, Shift 2

The current of 5A5 \, \text{A} flows in a square loop of sides 1m1 \, \text{m} placed in air. The magnetic field at the center of the loop is X2×107TX\sqrt{2} \times 10^{-7} \, \text{T}. The value of XX is:

  • A

    1010

  • B

    2020

  • C

    3030

  • D

    4040

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