MCQEasyJEE Main 2024 · 30 January, Shift 1Biot–Savart Law

Physics Question from JEE Main 2024 · 30 January, Shift 1

Two insulated circular loops A and B of radius aa, carrying a current II in anticlockwise direction, are arranged perpendicular to each other. The magnitude of the magnetic induction at the center will be:

  • A

    2aμ0I\frac{\sqrt{2}}{a}\mu_0 I

  • B

    μ0I2a\frac{\mu_0 I}{2a}

  • C

    μ0I2a\frac{\mu_0 I}{\sqrt{2}\,a}

  • D

    2μ0Ia\frac{2\mu_0 I}{a}

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