MCQMediumJEE Main 2024 · 30 January, Shift 1Circle Equation & Properties

Mathematics Question from JEE Main 2024 · 30 January, Shift 1

If the circles (x+1)2+(y+2)2=r2(x + 1)^2 + (y +2)^2 = r^2 and x2+y24x4y+4=0x^2 + y^2 - 4x - 4y + 4 = 0 intersect at exactly two distinct points, then:

  • A

    5<r<95 < r < 9

  • B

    0<r<70 < r < 7

  • C

    3<r<73 < r < 7

  • D

    1/2<r<71/2 < r < 7

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Practice more Circle Equation & Properties questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Related questions