MCQMediumJEE Main 2026 · 21 January, Shift 1Circle Equation & Properties

Mathematics Question from JEE Main 2026 · 21 January, Shift 1

Let PQ and MN be two straight lines touching the circle x2+y24x6y3=0x^2+y^2-4x-6y-3=0 at the points A and B respectively. Let O be the centre of the circle and AOB=π/3\angle AOB = \pi/3. Then the locus of the point of intersection of the lines PQ and MN is:

  • A

    x2+y218x12y25=0x^2+y^2-18x-12y-25=0

  • B

    3(x2+y2)18x12y+25=03(x^2+y^2)-18x-12y+25=0

  • C

    3(x2+y2)12x18y25=03(x^2+y^2)-12x-18y-25=0

  • D

    x2+y212x18y25=0x^2+y^2-12x-18y-25=0

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Practice more Circle Equation & Properties questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Related questions