MCQMediumJEE Main 2026 · 22 January, Shift 1Circle Equation & Properties

Mathematics Question from JEE Main 2026 · 22 January, Shift 1

Let the set of all values of rr, for which the circles (x+1)2+(y+4)2=r2(x + 1)^2 + (y + 4)^2 = r^2 and x2+y24x2y4=0x^2 + y^2 - 4x - 2y - 4 = 0 intersect at two distinct points be the interval (α,β)(\alpha, \beta). Then αβ\alpha\beta is equal to

  • A

    2525

  • B

    2121

  • C

    2424

  • D

    2020

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