Let the circle x²+y²=4 intersect the x-axis at points A(a,0) and… | JEE Main 2026 Mathematics PYQ

MCQMediumJEE Main 2026 · 28 January, Shift 2Circle Equation & Properties

Let the circle $x^2+y^2=4$ intersect the $x$ -axis at points $A(a,0)$ and $B(b,0)$ . Let $P(2\cos\alpha,2\sin\alpha)$ , $0<\alpha<\frac{\pi}{2}$ , and $Q(2\cos\beta,2\sin\beta)$ be two points on the circle such that $(\alpha-\beta)=\frac{\pi}{2}$ . Then the point of intersection of lines $AQ$ and $BP$ lies on:

A
$x^2+y^2-4x-4y-4=0$
B
$x^2+y^2-4x-4=0$
C
$x^2+y^2-4y-4=0$
D
$x^2+y^2-4x-4y=0$

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