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MCQEasyJEE 2024Isomerism (Structural, Stereoisomerism)

JEE Chemistry 2024 Question with Solution

Which one of the following will show geometrical isomerism?

  • A

    CH₃CH=CHCH₃

  • B

    CH₂=CBr₂

  • C

    CH₃CH=CHBr

  • D

    Cyclohexane

Answer

Correct answer:C

Step-by-step solution

Standard Method

Given: Four compounds are given and we need to identify which one shows geometrical isomerism.

Find: The compound that can exhibit geometrical isomerism.

Geometrical isomerism occurs when:

  1. A compound contains a double bond, so rotation is restricted.
  2. Each carbon of the double bond has two different groups attached.

From the extracted solution, option C satisfies these conditions. The compound CH₃CH=CHBr has a double bond and each doubly bonded carbon is attached to two different groups, so cis-trans isomerism is possible.

Conclusion: The correct option is C.

Condition Check

Given: We must test the condition for geometrical isomerism in each option.

Find: Which option has restricted rotation and different groups on both double-bonded carbons.

  • Option A: CH₃CH=CHCH₃
  • Option B: CH₂=CBr₂
  • Option C: CH₃CH=CHBr
  • Option D: Cyclohexane

the solution states that the relevant condition is that each carbon atom in the double bond must have two different groups or atoms attached.

Option C, CH₃CH=CHBr, fulfills this requirement. Therefore it shows geometrical isomerism.

The solution also explicitly states: "The Correct Option is C" and "The correct answer is option 3."

Conclusion: The correct option is C.

Common mistakes

  • Checking only for the presence of a double bond is not sufficient. A compound shows geometrical isomerism only when each carbon of the double bond has two different substituents. Always verify substituents on both double-bonded carbons.

  • Assuming every cyclic compound shows geometrical isomerism is incorrect. Cyclohexane itself does not satisfy the alkene-based condition discussed here. Do not choose a ring compound unless the required stereochemical restriction is actually present.

  • Ignoring substituent symmetry leads to wrong answers. If one carbon of the double bond has two identical groups, geometrical isomerism is not possible. Check for identical groups before concluding.

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