NVAMediumJEE Main 2024 · 29 January, Shift 2Circular Motion Dynamics

Physics Question from JEE Main 2024 · 29 January, Shift 2

A particle is moving in a circle of radius 50cm50 \, \text{cm} in such a way that at any instant the normal and tangential components of its acceleration are equal. If its speed at t=0t = 0 is 4m/s4 \, \text{m/s}, the time taken to complete the first revolution will be 1α[1e2π]\frac{1}{\alpha} [1 - e^{-2\pi}] seconds, where α\alpha is:

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