A bob of mass ‘m’ is suspended by a light string of length ‘L’. I… | JEE Main 2024 Physics PYQ

MCQMediumJEE Main 2024 · 29 January, Shift 2Circular Motion Dynamics

A bob of mass ‘ $m$ ’ is suspended by a light string of length ‘ $L$ ’. It is imparted a minimum horizontal velocity at the lowest point $A$ such that it just completes a half-circle reaching the topmost position $B$ . The ratio of kinetic energies $(\text{K.E.})_A : (\text{K.E.})_B$ is:

A
$3:2$
B
$5:1$
C
$2:5$
D
$1:5$

Answer & step-by-step solution

Practice more Circular Motion Dynamics questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Start free trial More on Circular Motion Dynamics

Answer & step-by-step solution

Practice more Circular Motion Dynamics questions

Related questions