The area (in sq. units) of the part of the circle x² + y² = 169 w… | JEE Main 2024 Mathematics PYQ

MCQMediumJEE Main 2024 · 29 January, Shift 1Circle Equation & Properties

The area (in sq. units) of the part of the circle $x^2 + y^2 = 169$ which is below the line $5x - y = 13$ is $\frac{\pi\alpha}{2\beta} - \frac{65}{2} + \frac{\alpha}{\beta}\sin^{-1}\left(\frac{12}{13}\right)$ , where $\alpha, \beta$ are coprime numbers. Then $\alpha + \beta$ is equal to:

A
$171$
B
$181$
C
$160$
D
$155$

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