NVAMediumJEE Main 2024 · 27 January, Shift 1Biot–Savart Law

Physics Question from JEE Main 2024 · 27 January, Shift 1

Two long, straight wires carry equal currents of 10A10 \, \text{A} each in opposite directions. The separation between the wires is 5.0cm5.0 \, \text{cm}. The magnitude of the magnetic field at a point PP midway between the wires is _____ μT\mu \text{T}.

(Given: μ0=4π×107T m A1\mu_0 = 4\pi \times 10^{-7} \, \text{T m A}^{-1})

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