MCQMediumJEE Main 2024 · 27 January, Shift 1Skew Lines & Shortest Distance

Mathematics Question from JEE Main 2024 · 27 January, Shift 1

The shortest distance between the lines x41=y+12=z3\frac{x - 4}{1} = \frac{y + 1}{2} = \frac{z}{-3} and xλ2=y+14=z25\frac{x - \lambda}{2} = \frac{y + 1}{4} = \frac{z - 2}{-5} is 65\frac{6}{\sqrt{5}}. The sum of all possible values of λ\lambda is:

  • A

    55

  • B

    88

  • C

    77

  • D

    1010

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