MCQMediumJEE Main 2023 · 12 April, Shift 1Carboxylic Acids

Chemistry Question from JEE Main 2023 · 12 April, Shift 1

The major product PP formed in the following sequence of reactions is:

Reaction sequence starting from an aromatic carboxylic acid side chain compound treated with SOCl2, R-NH2, LiAlH4 and H3O+, asking for the major product among given structures.
  • A

    The alkene is retained and the chain ends in a carbon bearing both −OH-\text{OH} and −NHR-\text{NHR}: phenyl−CH=CH−CH2−CH(OH)NHR-\text{CH}=\text{CH}-\text{CH}_2-\text{CH}(\text{OH})\text{NHR}

  • B

    The double bond has added HCl and the chain ends in −CH2OH-\text{CH}_2\text{OH}: phenyl−CH(NHR)−CH(Cl)−CH2−CH2OH-\text{CH}(\text{NHR})-\text{CH}(\text{Cl})-\text{CH}_2-\text{CH}_2\text{OH}

  • C

    The saturated amide: phenyl−CH2−CH2−CH2−CONHR-\text{CH}_2-\text{CH}_2-\text{CH}_2-\text{CONHR}

  • D

    The unsaturated amine: phenyl−CH=CH−CH2−CH2−NHR-\text{CH}=\text{CH}-\text{CH}_2-\text{CH}_2-\text{NHR}

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