Chemistry Question from JEE Main 2023 · 12 April, Shift 1

The alkene is retained and the chain ends in a carbon bearing both $-\text{OH}$ and $-\text{NHR}$: phenyl$-\text{CH}=\text{CH}-\text{CH}_2-\text{CH}(\text{OH})\text{NHR}$

The double bond has added HCl and the chain ends in $-\text{CH}_2\text{OH}$: phenyl$-\text{CH}(\text{NHR})-\text{CH}(\text{Cl})-\text{CH}_2-\text{CH}_2\text{OH}$

The saturated amide: phenyl$-\text{CH}_2-\text{CH}_2-\text{CH}_2-\text{CONHR}$

The unsaturated amine: phenyl$-\text{CH}=\text{CH}-\text{CH}_2-\text{CH}_2-\text{NHR}$