MCQMediumJEE Main 2023 · 12 April, Shift 1Cross Product

Mathematics Question from JEE Main 2023 · 12 April, Shift 1

Let λZ\lambda \in \mathbb{Z}, a=λi^+j^k^\vec{a} = \lambda \hat{i} + \hat{j} - \hat{k} and b=3i^j^+2k^\vec{b} = 3\hat{i} - \hat{j} + 2\hat{k}. Let c\vec{c} be a vector such that

(a+b+c)×c=0,ac=17andbc=20.(\vec{a} + \vec{b} + \vec{c}) \times \vec{c} = 0, \quad \vec{a} \cdot \vec{c} = -17 \quad \text{and} \quad \vec{b} \cdot \vec{c} = -20.

Then c×(λi^+j^+k^)2\left| \vec{c} \times (\lambda \hat{i} + \hat{j} + \hat{k}) \right|^2 is equal to:

  • A

    6262

  • B

    4646

  • C

    5353

  • D

    4949

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