JEE Physics 2023 Question with Solution

Given: Each diode has forward bias resistance $25 \, \Omega$.

Find: The correct current ratio in the circuit.

Analyzing the circuit. From the given circuit, we see that diodes $D_1$ and $D_3$ are conducting, while $D_2$ is reverse biased. Hence, current $I_1$ will be split between $I_3$ and $I_4$, and $I_2 = 0$.

Using Kirchhoff's Current Law (KCL), we have:

$$I_1 = I_2 + I_4 + I_3 = 2I_2$$

Thus, the ratio is written in the solution as:

$$\frac{I_1}{I_2} = 2$$

However, the solution also marks the correct option as D, which disagrees with the shown working and with the listed options. Based on the authoritative option marker on the solution, the correct option is D.