Molar mass of the hydrocarbon which on ozonolysis consumes one mole of per mole of and gives one mole each of ethanol and propanone is:
JEE Chemistry 2023 Question with Solution
Answer
Correct answer:70
Step-by-step solution
Standard Method
Given: The hydrocarbon consumes one mole of per mole of on ozonolysis and gives one mole each of ethanol and propanone.
Find: The molar mass of .
From the given reaction in the solution:
Thus, the hydrocarbon is pent-2-yne with molecular formula .
Its molecular mass is:
Therefore, the molar mass of the hydrocarbon is .
Common mistakes
Identifying the hydrocarbon incorrectly from the ozonolysis products is a common mistake. This is wrong because the products must be matched to the correct alkyne skeleton. Use the given ethanol and propanone fragments to reconstruct the parent hydrocarbon carefully.
Using the wrong molecular formula for pent-2-yne can lead to an incorrect molar mass. This is wrong because alkynes follow the formula . For , use before calculating the mass.
Practice more Alkynes (Acidic Nature, Reactions) questions
Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step — free to start.
Related questions
- Consider the following reaction: The product Y formed is:Medium · JEE 2026
- The dibromo compound P (molecular formula: C9H10Br2) when heated with excess sodamide followed by treatment…Medium · JEE 2026
- Identify (P)Medium · JEE 2026
- Given below are two statements for the following reaction sequence: Statement I: Compound Z gives a yellow…Medium · JEE 2026
- An optically active alkyl halide C4H9Br [A] reacts with hot KOH dissolved in ethanol and forms alkene [B] as…Medium · JEE 2025
- View questionMedium · JEE 2025
